document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=41188>Question 41188</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I solve the below equation?  I know I have to add the two absolute value equations, but can not find any information on how to add them. \r<BR>\n" );
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document.write( "If f(x) = | x + 2| and g(x) = | x - 3 |, then (f + g)(x) =  </SPAN>\n" );
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document.write( "f(x) = x+2, if x>=-2<BR>\n" );
document.write( "f(x) =-x-2, if x<-2\r<BR>\n" );
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document.write( "and \r<BR>\n" );
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document.write( "g(x) = x-3 , if x>=3<BR>\n" );
document.write( "g(x) = -x+3, if x<3\r<BR>\n" );
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document.write( "to write (f+g)(x), we take the intersection of the domains of these two functions.\r<BR>\n" );
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document.write( "(f+g)(x)= (-x-2)+(-x+3), if  x<-2<BR>\n" );
document.write( "(f+g)(x)= (x+2)+(-x+3), if  -2<=x<3<BR>\n" );
document.write( "(f+g)(x)= (x+2)+(x-3),  if x>=3\r<BR>\n" );
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document.write( "if we do these additions;\r<BR>\n" );
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document.write( "(f+g)(x)= -2x+1, if  x<-2<BR>\n" );
document.write( "(f+g)(x)= 5    , if  -2<=x<3<BR>\n" );
document.write( "(f+g)(x)= 2x-1,  if x>=3<BR>\n" );
document.write( " </SPAN>\n" );
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