document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=374828>Question 374828</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1. Find sin B and cos B if tan B is 40/9.<BR>\n" );
document.write( "2. Find sin A and tan A if cos A is 3&#8730;34/34.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #266559 by </B><A HREF=/tutors/aboutme.mpl?userid=vasumathi><B>vasumathi(46)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vasumathi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=266559\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. Find sin B and cos B if tan B is 40/9\r<BR>\n" );
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document.write( "Solution: tan B = 40/9 <BR>\n" );
document.write( "so opposite side = 40<BR>\n" );
document.write( "and adjacent side = 9<BR>\n" );
document.write( "we can calculate the hypotenuse as follows...<BR>\n" );
document.write( "hypotenuse = sqrt(40^2+9^2) = sqrt(1600 + 81) = sqrt(1681)= 41<BR>\n" );
document.write( "sin B = opposite side/hypotenuse = 40/41<BR>\n" );
document.write( "cosB = adjacent side/ hypotenuse= 9/41<BR>\n" );
document.write( "2. Find sin A and tan A if cos A is 3&#8730;34/34.<BR>\n" );
document.write( "Solution: cos A = 3sqrt(34)/34<BR>\n" );
document.write( "sin^2A + cos^2A = 1<BR>\n" );
document.write( "sin^2(A) +9*34/34^2<BR>\n" );
document.write( "sin^2(A) + 306/1156=1<BR>\n" );
document.write( "sin^2(A) = 1-306/1156= 850/1156=25*34/34*34<BR>\n" );
document.write( "sin(A) = 5 sqrt 34/34<BR>\n" );
document.write( "tan A = sin A / cosA= (5 sqrt 34/34)/(3 sqrt(34)/34)= 5/3<BR>\n" );
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