document.write( "Question 374768: A motor boat takes 5 hrs to travel 300 mi going upstream. The return trip takes 2hrs. going downstream. What is the rate of the boat in still water and what is the rate of the current? \n" ); document.write( "
Algebra.Com's Answer #266511 by mananth(16946)\"\" \"About 
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let rate of boat in still water be x mph
\n" ); document.write( "rate of current be y
\n" ); document.write( "..
\n" ); document.write( "downstream speed = x+y
\n" ); document.write( "upstream rate = x-y
\n" ); document.write( "..
\n" ); document.write( "t = d/r
\n" ); document.write( "upstream
\n" ); document.write( "5 = 300/(x-y)
\n" ); document.write( "5(x-y)=300
\n" ); document.write( "5x-5y=300
\n" ); document.write( "/5
\n" ); document.write( "x-y=60.......................1
\n" ); document.write( "downstream
\n" ); document.write( "2= 300/(x+y)
\n" ); document.write( "2(x+y)=300
\n" ); document.write( "2x+2y=300
\n" ); document.write( "/2
\n" ); document.write( "x+y =150.....................2
\n" ); document.write( "...
\n" ); document.write( "Add 1 & 2
\n" ); document.write( "2x=60+150
\n" ); document.write( "2x=210
\n" ); document.write( "/2
\n" ); document.write( "x= 105 mph rate of boat in still water
\n" ); document.write( "x-y =60
\n" ); document.write( "plug x
\n" ); document.write( "105-y=60
\n" ); document.write( "y = 105-60
\n" ); document.write( "y=45 mph
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( "
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