document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=40995>Question 40995</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation, in standard form, with all integer coefficients, of the line perpendicular to 3x-4y=9 and passing through (-2,-1) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26650 by </B><A HREF=/tutors/aboutme.mpl?userid=zeynep><B>zeynep(43)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=zeynep><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26650\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the formula for the slope of a line is; -(coefficient of x/coefficient of y)<BR>\n" );
document.write( "so the slope of the line, 3x-4y=9, is ; 3/4.\r<BR>\n" );
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document.write( "the product of the slopes of two perpendicular lines is -1.\r<BR>\n" );
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document.write( "Therefore, the slope of the new line is -1/(3/4)=-4/3\r<BR>\n" );
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document.write( "A line going through the point (a,b) and having slope of m would have the equation;<BR>\n" );
document.write( "y-a=m(x-b)\r<BR>\n" );
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document.write( "Therefore the equation for our new line is;\r<BR>\n" );
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document.write( "y+1=-4/3(x+2) <BR>\n" );
document.write( "y+1=-4/3x-8/3 (if we multiply both sides by 3)<BR>\n" );
document.write( "3y+3=-4x-8<BR>\n" );
document.write( "4x+3y+11=0\r<BR>\n" );
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document.write( " </SPAN>\n" );
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