document.write( "Question 374754: Hello, I recently took an assessment and now I'm doing a test revision. This is one of the problems I got wrong:\r
\n" ); document.write( "\n" ); document.write( "6(2y+5)-4(y-3)=7\r
\n" ); document.write( "\n" ); document.write( "Can you help me solve the equation for y? I tried and got 25 over 8 (as in a fraction), but I don't remember what I did, because the test was almost 3 weeks ago.
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Algebra.Com's Answer #266494 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"6%282y%2B5%29-4%28y-3%29=7\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"12y%2B30-4y%2B12=7\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"8y%2B42=7\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"8y=7-42\" Subtract \"42\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"8y=-35\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-35%29%2F%288%29\" Divide both sides by \"8\" to isolate \"y\".\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"y=-35%2F8\" \r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, feel free to check out my tutoring website\r
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\n" ); document.write( "\n" ); document.write( "Jim
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