document.write( "Question 41177: use Gauss-Jordan elimination to solve the following system of equations.
\n" ); document.write( "3x+5y=7
\n" ); document.write( "6x-y=-8
\n" ); document.write( "

Algebra.Com's Answer #26649 by zeynep(43)\"\" \"About 
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3x+5y=7
\n" ); document.write( "6x-y=-8\r
\n" ); document.write( "\n" ); document.write( "Let's multiply the second equation by 5 to create opposite coefficients for y.\r
\n" ); document.write( "\n" ); document.write( "3x+5y=7
\n" ); document.write( "30x-5y=-40\r
\n" ); document.write( "\n" ); document.write( "Now, let''s add the two equations to drop out y.\r
\n" ); document.write( "\n" ); document.write( "33x=-33y (divide each side by 33)
\n" ); document.write( "33x/33=-33/33
\n" ); document.write( "x=-1\r
\n" ); document.write( "\n" ); document.write( "Let's plug the value of x in the first equation (you may plug it in the second equation as well);\r
\n" ); document.write( "\n" ); document.write( "3.(-1)+5y=7
\n" ); document.write( "-3+5y=7 (move -3 to the right of the equation)
\n" ); document.write( "5y=7+3
\n" ); document.write( "5y=10 (divide each side by 5)
\n" ); document.write( "5y/5=10/5
\n" ); document.write( "y=2
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