document.write( "Question 374628: Factor the four-term polynomial by grouping.\r
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Algebra.Com's Answer #266461 by jim_thompson5910(35256) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( " $\"x%5E3%2B5x%5E2%2B3x%2B15\"$ Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( " $\"%28x%5E3%2B5x%5E2%29%2B%283x%2B15%29\"$ Group like terms\r
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\n" ); document.write( "\n" ); document.write( " $\"x%5E2%28x%2B5%29%2B3%28x%2B5%29\"$ Factor out the GCF $\"x%5E2\"$ out of the first group. Factor out the GCF $\"3\"$ out of the second group\r
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\n" ); document.write( "\n" ); document.write( " $\"%28x%5E2%2B3%29%28x%2B5%29\"$ Since we have the common term $\"x%2B5\"$ , we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So $\"x%5E3%2B5x%5E2%2B3x%2B15\"$ factors to $\"%28x%5E2%2B3%29%28x%2B5%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "In other words, $\"x%5E3%2B5x%5E2%2B3x%2B15=%28x%5E2%2B3%29%28x%2B5%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, feel free to check out my tutoring website\r
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\n" ); document.write( "\n" ); document.write( "Jim \n" ); document.write( "

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