document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=374530>Question 374530</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the question is: given a right triangle with a perimeter of 60 and an altitude to the hypotnuse with a length of 12 what is the length of each side?\r<BR>\n" );
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document.write( "i tried a lot using substitution its just too complicated i need an explanation too plz asap </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #266448 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=266448\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A suggestion:  Let x  = the unknown leg, and y = the hypotenuse.  Then <BR>\n" );
document.write( "from the perimeter condition, x+y+12 = 60, or x+y = 48, or y = 48 - x.<BR>\n" );
document.write( "From the right-triangle condition, use the Pythagorean identity : <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12%5E2+%2B+x%5E2+=+y%5E2 ALIGN=MIDDLE  ALT=\"12%5E2+%2B+x%5E2+=+y%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "Substituting, we get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=144+%2B+x%5E2+=+%2848-x%29%5E2 ALIGN=MIDDLE  ALT=\"144+%2B+x%5E2+=+%2848-x%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Now see if there will be any progress... </SPAN>\n" );
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