document.write( "Question 374395: Blaise rode his bike to his friend Elroy's house, which was 15 miles away. After he had been riding for half an hour, he go a flat tire. He walked his bike the rest of the way. The total trip took him 3 hours. If his walking rate was one-fourth as fast as his riding rate, how fast did he ride?
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #266428 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
Blaise rode his bike to his friend Elroy's house, which was 15 miles away.
\n" ); document.write( " After he had been riding for half an hour, he go a flat tire.
\n" ); document.write( " He walked his bike the rest of the way. The total trip took him 3 hours.
\n" ); document.write( "If his walking rate was one-fourth as fast as his riding rate, how fast did he ride?
\n" ); document.write( ":
\n" ); document.write( "Let w = his walking rate
\n" ); document.write( "then
\n" ); document.write( "4w = his riding rate
\n" ); document.write( ":
\n" ); document.write( "Given that he rode .5 hrs, then he walked: 3 - .5 = 2.5 hrs
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation: Dist = time * speed
\n" ); document.write( "2.5w + .5(4w) = 15
\n" ); document.write( ":
\n" ); document.write( "2.5w + 2w = 15
\n" ); document.write( ":
\n" ); document.write( "4.5w = 15
\n" ); document.write( "w = $\"15%2F4.5\"$
\n" ); document.write( "w = 3 $\"1%2F3\"$ mph is his walking speed
\n" ); document.write( "then
\n" ); document.write( "4(3 $\"1%2F3\"$ ) = 13 $\"1%2F3\"$ mph is his riding speed
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution using decimals
\n" ); document.write( "2.5(3.33) + .5(13.33) = 14.99 ~ 15, confirms our solutions \n" ); document.write( "

\n" );