document.write( "Question 374509: The perimeter of a rectangle is 81 cm and the area is 407 cm^2. Set up a quadratic equation and find the dimensions of the rectangle. (show your work) \n" ); document.write( "
Algebra.Com's Answer #266422 by checkley79(3341)\"\" \"About 
You can put this solution on YOUR website!
81=2L+2W
\n" ); document.write( "407=LW OR L=407/W
\n" ); document.write( "81=2(407/W)+2W
\n" ); document.write( "81=814/W+2W
\n" ); document.write( "81=(814+2W*W)/W
\n" ); document.write( "81=(814+2W^2)/W
\n" ); document.write( "81W=814+2W^2
\n" ); document.write( "2W^2-81W+814=0
\n" ); document.write( "(2W-37)(W-22)=0
\n" ); document.write( "2W-37=0
\n" ); document.write( "2W=37
\n" ); document.write( "W=18.5 ans.
\n" ); document.write( "W-22=0
\n" ); document.write( "W=22 ans.
\n" ); document.write( "L=407/18.5
\n" ); document.write( "L=22 ANS.
\n" ); document.write( "L=407/22=18.5 ANS.
\n" ); document.write( "PROOF:
\n" ); document.write( "81=2*22+2*18.5
\n" ); document.write( "81=44+37
\n" ); document.write( "81=81\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );