document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=41272>Question 41272</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please simplify and solve<BR>\n" );
document.write( "1. 4x+y=2<BR>\n" );
document.write( "x+2y=4<BR>\n" );
document.write( "2. -x-5y=-6<BR>\n" );
document.write( "3x+y=4<BR>\n" );
document.write( "3. -3x+2y=7<BR>\n" );
document.write( "x+y=-7<BR>\n" );
document.write( "4.2x+3y=5<BR>\n" );
document.write( "-x+2y=1<BR>\n" );
document.write( "5.-x+2y=-6<BR>\n" );
document.write( "4x-3y=4<BR>\n" );
document.write( "6.4x+y=-6<BR>\n" );
document.write( "3x-2y=1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26642 by </B><A HREF=/tutors/aboutme.mpl?userid=zeynep><B>zeynep(43)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=zeynep><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26642\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1.  4x+y=2<BR>\n" );
document.write( "    x+2y=4\r<BR>\n" );
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document.write( "Let's multiply the first equation by -2 to create opposite coefficients for y.\r<BR>\n" );
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document.write( "-8x-2y=-4<BR>\n" );
document.write( "  x+2y= 4\r<BR>\n" );
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document.write( "Now when we add these equations side by side, we will drop out y.\r<BR>\n" );
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document.write( "-7x + 0 = 0<BR>\n" );
document.write( "-7x = 0      (divide each side by -7)\r<BR>\n" );
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document.write( "-7x/-7 = 0/-7<BR>\n" );
document.write( "x = 0\r<BR>\n" );
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document.write( "To find the value of y, we will insert the value of x in the first equation(you may insert it into the second equation as well);\r<BR>\n" );
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document.write( "4.0+y = 2<BR>\n" );
document.write( "0+y = 2<BR>\n" );
document.write( "y=2\r<BR>\n" );
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document.write( "2. -x-5y=-6<BR>\n" );
document.write( "    3x+y=4\r<BR>\n" );
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document.write( "Let's multiply the first equation by 3 to create opposite coefficients for x;\r<BR>\n" );
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document.write( "-3x-15y=-18<BR>\n" );
document.write( "3x+y=4\r<BR>\n" );
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document.write( "Now when we add the two equations side by side we will drop out x;\r<BR>\n" );
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document.write( "0-14y = -14<BR>\n" );
document.write( "-14y = -14 (divide each side by -14)\r<BR>\n" );
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document.write( "14y/-14 = -14/-14<BR>\n" );
document.write( "y = 1\r<BR>\n" );
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document.write( "Now let's insert the value of y into the second equation to find the value of x;<BR>\n" );
document.write( "3x+1=4 (move 1 to the right of the equation)<BR>\n" );
document.write( "3x= 4-1<BR>\n" );
document.write( "3x=3    (divide each side by 3)<BR>\n" );
document.write( "3x/3=3/3<BR>\n" );
document.write( "x=1\r<BR>\n" );
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document.write( "As you see, to solve these kinds of equations we try to leave out one of the variables. To do this;<BR>\n" );
document.write( "1. multiply one or both of the equations by a number that will create opposite coefficients for either x or y.<BR>\n" );
document.write( "2. add the equations side by side.<BR>\n" );
document.write( "3. Now you are left with one variable. Solve the equation for remaining variable.<BR>\n" );
document.write( "4. Plug the value you found in the third step in on eof the given equations and find the other variable.\r<BR>\n" );
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document.write( "I hope this helps and you can solve the remaining questions. If you cannot, let me know.<BR>\n" );
document.write( " </SPAN>\n" );
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