document.write( "Question 374054: Find the equation of the bisector of the pair of acute angles formed by the lines 4x-3y= 8 and 2x+y=4 \n" ); document.write( "
Algebra.Com's Answer #266411 by Alan3354(69443)\"\" \"About 
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Find the intersection of the 2 lines, = (2,0)
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\n" ); document.write( "Find the slope of the 2 lines:
\n" ); document.write( "4x-3y = 8 m1 = 4/3
\n" ); document.write( "2x+y = 4 m2 = -2
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\n" ); document.write( "The slope is the arctan of the angle the line makes with the x-axis
\n" ); document.write( "arctan(4/3) =~ 53.13º
\n" ); document.write( "arctan(-2) =~ -63.435º
\n" ); document.write( "The angle between them is 116.565º (in Quad 1), so the acute angles are 83.435º
\n" ); document.write( "The bisector makes and angle of 53.15 + (83.435)/2 = 84.8675º with the x-axis
\n" ); document.write( "Its slope = tan(84.8675) = 11.133
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\n" ); document.write( "Use y = mx + b and the point (2,0)
\n" ); document.write( "0 = 2*11.133 + b
\n" ); document.write( "b = -22.266
\n" ); document.write( "Equation is y = 11.133x - 22.266
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