document.write( "Question 374255: Use law of logarithms to evaluate:
\n" ); document.write( "log5 (1000/8)= ?\r
\n" ); document.write( "\n" ); document.write( "*log(1000/8)to the base of 5.
\n" ); document.write( "

Algebra.Com's Answer #266393 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
I'm not sure what \"law of logarithms\" is so thsi may not be what you are looking for.

\n" ); document.write( "\"log%285%2C+%281000%2F8%29%29\"
\n" ); document.write( "First we'll simplify the argument. 1000/8 = 125:
\n" ); document.write( "\"log%285%2C+%28125%29%29\"
\n" ); document.write( "\"125+=+5%5E3\" so this becomes:
\n" ); document.write( "\"log%285%2C+%285%5E3%29%29\"
\n" ); document.write( "If you understand what this logarithm stands for then you know that this simplifies to 3. If not, then we can use a property of logarithms, \"log%28a%2C+%28p%5Eq%29%29+=+q%2Alog%28a%2C+%28p%29%29\", to move the exponent of the argument out in front:
\n" ); document.write( "\"3%2Alog%285%2C+%285%29%29\"
\n" ); document.write( "Since \"log%285%2C+%285%29%29+=+1\" by definition, this becomes:
\n" ); document.write( "3*1
\n" ); document.write( "or
\n" ); document.write( "3
\n" ); document.write( "
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