document.write( "Question 374315: a rectangular lot has a perimeter of 40 meters and an area of 96 sq. meters. what are the dimensions of a lot? \n" ); document.write( "

Algebra.Com's Answer #266380 by checkley79(3341) $\"\"$ $\"About$

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XY=96 OR X=90/Y
\n" ); document.write( "2X+2Y=40
\n" ); document.write( "REPLACING X IN THE SECOND EQUATION WITH (90/Y).
\n" ); document.write( "2(90/Y)+2Y=40
\n" ); document.write( "180/Y+2Y=40
\n" ); document.write( "(180+2Y*Y)/Y=40
\n" ); document.write( "(2Y^2+180)/Y=40 CROSS MULTIPLY.
\n" ); document.write( "2Y^2+180=40Y
\n" ); document.write( "2Y^2-40Y+180=0
\n" ); document.write( "2(Y^2-20Y+90)=0
\n" ); document.write( " $\"y+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$
\n" ); document.write( "y=(20+-sqrt[-20^2-4*1*90])/2*1
\n" ); document.write( "y=(20+-sqrt[400-360])/2
\n" ); document.write( "y=(20+-sqrt40)/2
\n" ); document.write( "y=(20+-6.325)/2
\n" ); document.write( "y=(20+6.325)/2
\n" ); document.write( "y=26.325/2
\n" ); document.write( "y=13.1625 ans.
\n" ); document.write( "x=90/13.1625
\n" ); document.write( "x=6.8376 ans.
\n" ); document.write( "Proof:
\n" ); document.write( "2*13.625+2*6.8376=40
\n" ); document.write( "26.325+13.675=40
\n" ); document.write( "40=40
\n" ); document.write( " \n" ); document.write( "

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