document.write( "Question 374291: The sum of the reciprocals of two numbers is 4/15 and their product is 60. what are the numbers? \n" ); document.write( "
Algebra.Com's Answer #266368 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
let the numbers be x & y
\n" ); document.write( "...
\n" ); document.write( "1/x +1/y = 4/15
\n" ); document.write( "(x+y)/xy = 4/15
\n" ); document.write( "15(x+y)=4xy
\n" ); document.write( "15x+15y=4xy...................1
\n" ); document.write( "...
\n" ); document.write( "xy =60
\n" ); document.write( "x= 60/y
\n" ); document.write( "...
\n" ); document.write( "15x+15y=4xy
\n" ); document.write( "15*60/y +15y = 4*60
\n" ); document.write( "(900+15y^2)/y = 240
\n" ); document.write( "900+15y^2=240y
\n" ); document.write( "15y^2-240y+900=0
\n" ); document.write( "/15
\n" ); document.write( "y^2-16y+60=0
\n" ); document.write( "y^2-10y-6y+60=0
\n" ); document.write( "y(y-10)-6(y-10)=0
\n" ); document.write( "(y-10)(y-6)=0
\n" ); document.write( "y = 6 OR 10
\n" ); document.write( "the numbers are 6 & 10
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( "
\n" );