document.write( "Question 374272: How many kilograms of chocolates costing Php80.00 per kilogram must be mixed with 6 kilograms of chocolates that cost Php100.00 per kilogram to produce a mixture that can be sold for Php85.00 per kilogram? \n" ); document.write( "

Algebra.Com's Answer #266361 by Edwin McCravy(20055) $\"\"$ $\"About$

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How many kilograms of chocolates costing Php80.00 per kilogram must be mixed with 6 kilograms of chocolates that cost Php100.00 per kilogram to produce a mixture that can be sold for Php85.00 per kilogram?
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document.write( "Let x = number of kilograms of lower priced chocolates to be used.\r\n" );
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document.write( "There are x kilograms of lower-priced chocolate\r\n" );
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document.write( "There are 6 kilograms of higher-priced chocolates\r\n" );
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document.write( "There are x+6 kilograms of mixed chocolates\r\n" );
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document.write( "Value of the lower-priced chocolates = (Php80.00)(x)\r\n" );
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document.write( "Value of the higher priced chocolates  = (Php100.00)(6)\r\n" );
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document.write( "Value of the mixed chocolates = (Php85.00)(x+6)\r\n" );
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document.write( "Value                 Value                Value\r\n" );
document.write( "  of                    of                   of\r\n" );
document.write( "lower         +      higher        =       mixed  \r\n" );
document.write( "priced               priced              chocolates \r\n" );
document.write( "chocolates          chocolates\r\n" );
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document.write( "   80.00x     +      (100.00)(6)   =     (85.00)(x+6)\r\n" );
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document.write( "                        \r\n" );
document.write( "               80x + 600 =  85(x + 6)\r\n" );
document.write( "               80x + 600 =  85x + 510\r\n" );
document.write( "              -85x       = -85x\r\n" );
document.write( "              ------------------------\r\n" );
document.write( "               -5x + 600 =        510\r\n" );
document.write( "                   - 600         -600\r\n" );
document.write( "               -----------------------\r\n" );
document.write( "               -5x       =        -90\r\n" );
document.write( "                       x = 18\r\n" );
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document.write( "18 kilograms of the lower-priced chocolates.\r\n" );
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document.write( "Edwin

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