document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=374269>Question 374269</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If y varies as x cubed, what must be the value of x if the value of y is to be doubled? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #266360 by </B><A HREF=/tutors/aboutme.mpl?userid=Jk22><B>Jk22(389)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Jk22><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Jk22><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=266360\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If y varies as x cubed, then we have : y(x)=x^3 <BR>\n" );
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document.write( "let double y, and find the new value of x called x' : y'(x) = 2y(x) = x'^3, <BR>\n" );
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document.write( "x' = (2y(x))^(1/3) = 2^(1/3)(x^3)^(1/3) = 2^(1/3)x, <BR>\n" );
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document.write( " hence x has to be multiplied by the 3rd-root of two, or by 2^(1/3) </SPAN>\n" );
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