document.write( "Question 374097: Find two integers whose product is 104 such that one of the integers is three less than twice the other integer. \n" ); document.write( "
Algebra.Com's Answer #266355 by rfadrogane(214)\"\" \"About 
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Find two integers whose product is 104 such that one of the integers is three less than twice the other integer.
\n" ); document.write( "Sol'n:
\n" ); document.write( " Let x = the 1st integer
\n" ); document.write( " y = the 2nd integer
\n" ); document.write( " xy = 104 ----(1)
\n" ); document.write( " x = 2y - 3 ----(2)
\n" ); document.write( "substitute (2)into (1)
\n" ); document.write( " y(2y-3)=104
\n" ); document.write( " 2y^2 - 3y - 104 = 0, factor
\n" ); document.write( " (y-8)(2y+13)= 0
\n" ); document.write( " y = 8 & -6.5
\n" ); document.write( " from (1)
\n" ); document.write( " x = 104/y, subs. the value of y to find the value of x.
\n" ); document.write( " let y = 8,
\n" ); document.write( " x = 104/8 = 13
\n" ); document.write( " let y = -6.5
\n" ); document.write( " x = 104/(-6.5) = -16
\n" ); document.write( "and finally:
\n" ); document.write( " when x = 13, y = 8 -----answer
\n" ); document.write( "and, when x = -16, y = -6.5 -----answer
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