document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=374248>Question 374248</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the logarithmic equation algebraically. Approximate the result to three decimal places. (If there is no solution, enter NO SOLUTION.) ln x + ln(x + 1) = 2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #266340 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=266340\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The logarithmic equation can be reduced to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2+%2B+x+-+e%5E2+=+0 ALIGN=MIDDLE  ALT=\"x%5E2+%2B+x+-+e%5E2+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Using the quadratic formula, we get<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-1+%2B-+sqrt%28+1%2B4e%5E2+%29%29%2F2+ ALIGN=MIDDLE  ALT=\"x+=+%28-1+%2B-+sqrt%28+1%2B4e%5E2+%29%29%2F2+\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Only the value <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-1+%2Bsqrt%28+1%2B4e%5E2+%29%29%2F2+ ALIGN=MIDDLE  ALT=\"x+=+%28-1+%2Bsqrt%28+1%2B4e%5E2+%29%29%2F2+\"   DISABLED_style= \"max-width:90%; height:auto;\" > will satisfy the original equation, and so this is the final answer.  And that my STUDENT, is how it's done... </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );