document.write( "Question 374237: I am having trouble solving the following propositional logic proofs. \r
\n" ); document.write( "\n" ); document.write( "1. Conclusion: N + Y
\n" ); document.write( "1. K > (N & P)
\n" ); document.write( "2. S > (X & Y)
\n" ); document.write( "3. S + K
\n" ); document.write( "2. Conclusion: ~Q > ~M
\n" ); document.write( "1. M > [ Q + ~(E + H) ]
\n" ); document.write( "2. ~E > H
\n" ); document.write( "3. Conclusion: A & D
\n" ); document.write( "1. ~D > (F & P)
\n" ); document.write( "2. ~A > ~(F + P)
\n" ); document.write( "3. (F <=> P) > (~~D & A)
\n" ); document.write( "4. Conclusion: F > (Y > F)
\n" ); document.write( "1. Q
\n" ); document.write( "5. Conclusion: ~(~Q > ~X) > ~J
\n" ); document.write( "1.J > (M > Q)
\n" ); document.write( "2. X > (M + V)
\n" ); document.write( "3. J > (V > ~X)
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Algebra.Com's Answer #266334 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'll do the first one to get you started.\r
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document.write( "1.   K > (N & P)\r\n" );
document.write( "2.   S > (X & Y)\r\n" );
document.write( "3.   S + K                             :. N+Y\r\n" );
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document.write( "4.   [K > (N & P)] & [S > (X & Y)]              1,2 Conjunction\r\n" );
document.write( "5.   (N & P) + (X & Y)                          4,3 Constructive Dilemma\r\n" );
document.write( "6.   [(N & P) + X] & [(N & P) + Y]              5   Distibution\r\n" );
document.write( "7.   [(N & P) + Y] & [(N & P) + X]              6   Commutation\r\n" );
document.write( "8.   (N & P) + Y                                7   Simplification\r\n" );
document.write( "9.   Y + (N & P)                                8   Commutation\r\n" );
document.write( "10.  (Y + N) & (Y + P)                          9   Distribution\r\n" );
document.write( "11.  Y + N                                      10  Simplification\r\n" );
document.write( "12.  N + Y                                      11  Commutation\r\n" );
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