document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=374234>Question 374234</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What length on the circumference would a 20degree angle span on a 16 inch flywheel? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #266332 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=266332\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The formula to use is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s+=+r%2Atheta ALIGN=MIDDLE  ALT=\"s+=+r%2Atheta\"   DISABLED_style= \"max-width:90%; height:auto;\" >, where s  =arc length, r = radius, and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=theta ALIGN=MIDDLE  ALT=\"theta\"   DISABLED_style= \"max-width:90%; height:auto;\" > = angle in radians.  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=theta+=+20%2A%28pi%2F180%29+=+pi%2F9 ALIGN=MIDDLE  ALT=\"theta+=+20%2A%28pi%2F180%29+=+pi%2F9\"   DISABLED_style= \"max-width:90%; height:auto;\" >radians.  The radius of the flywheel is 8inches.  Thus <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s+=+8%2A%28pi%2F9%29+=+8pi%2F9 ALIGN=MIDDLE  ALT=\"s+=+8%2A%28pi%2F9%29+=+8pi%2F9\"   DISABLED_style= \"max-width:90%; height:auto;\" >inches, approximately 2.79 inches. </SPAN>\n" );
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