document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=374212>Question 374212</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the addition method if possible?<BR>\n" );
document.write( "3x+9y=9<BR>\n" );
document.write( "-x+5y=-3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #266324 by </B><A HREF=/tutors/aboutme.mpl?userid=dondon><B>dondon(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dondon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=266324\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x + 9y = 9 (number this equation as equation i)<BR>\n" );
document.write( "-x + 5y = -3 (number this equation as equation ii)\r<BR>\n" );
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document.write( "Now multiply equation ii) by 3 which gives:\r<BR>\n" );
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document.write( "-3x + 15y = -9 (number this equation as equation iii)\r<BR>\n" );
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document.write( "Now add equation i) and equation iii) which gives:\r<BR>\n" );
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document.write( "   24y = 0<BR>\n" );
document.write( "=> y = 0\r<BR>\n" );
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document.write( "Now plug this obtained value of y in any of equation i) or ii) to get value of x:<BR>\n" );
document.write( "plugging in i)\r<BR>\n" );
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document.write( "   3x + 9(0) = 9<BR>\n" );
document.write( "=> 3x = 9<BR>\n" );
document.write( "=> x = 3\r<BR>\n" );
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document.write( "so we get x = 3 & y = 0 as the answer. </SPAN>\n" );
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