document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=374005>Question 374005</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of the line that bisects the first quadrant. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #266318 by </B><A HREF=/tutors/aboutme.mpl?userid=rfadrogane><B>rfadrogane(214)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfadrogane><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rfadrogane><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=266318\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the equation of the line that bisects the first quadrant.<BR>\n" );
document.write( " Sol'n:<BR>\n" );
document.write( "  since it will bisect the first quadrant, it pass through the origin having a coordinate of (0,0) and also have a slope of 1 (m=1).<BR>\n" );
document.write( " from slope-intercept form:<BR>\n" );
document.write( "  y-y1 = m(x-x1)@ (0,0) and m = 1.<BR>\n" );
document.write( " thus,<BR>\n" );
document.write( "  y-0 = 1(x-0)<BR>\n" );
document.write( "   y = x ---answer<BR>\n" );
document.write( "   </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );