document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=295913>Question 295913</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if theta=-pi divided by 3, what is the value of y? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #266303 by </B><A HREF=/tutors/aboutme.mpl?userid=rfadrogane><B>rfadrogane(214)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfadrogane><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rfadrogane><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=266303\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if theta=-pi divided by 3, what is the value of y?\r<BR>\n" );
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document.write( "sol'n:<BR>\n" );
document.write( "  take tangent on both side<BR>\n" );
document.write( "   tan (theta)= tan (-pi/3)<BR>\n" );
document.write( "    from polar equation<BR>\n" );
document.write( "   tan (theta)= y/x and tan (-pi/3)= - sq. rt of 3<BR>\n" );
document.write( "thus;<BR>\n" );
document.write( "  y/x = - sq. root of 3<BR>\n" );
document.write( "  y = - sq.rt 3 times x<BR>\n" );
document.write( "  </SPAN>\n" );
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