document.write( "Question 374128: i)- Solve the following equations for 0° < x < 360°.\r
\n" ); document.write( "\n" ); document.write( "a) 2sinx cosx = 3 sinx\r
\n" ); document.write( "\n" ); document.write( "b) 1 - cosx = √3
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Algebra.Com's Answer #266299 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
a) \"+++2sin%28x%29%2Acos%28x%29+=+3%2Asin%28x%29\"
\n" ); document.write( "\"2cos%28x%29=3\"
\n" ); document.write( "\"cos%28x%29=3%2F2\"
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\n" ); document.write( "\n" ); document.write( "b) \"+++1+-+cos%28x%29+=sqrt%283%29\"
\n" ); document.write( "\"cos%28x%29=1-sqrt%283%29\"
\n" ); document.write( "\"cos%28x%29=-0.7321\"
\n" ); document.write( "\"highlight%28x=137.1%29\"degrees and \"highlight%28222.9%29\"degrees
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