document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=374175>Question 374175</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man who can walk 4 miles per hour takes a walk into the country on a holiday. He is away for 6 hours. How far does he go if he return by bicycle at the average rate of 12 miles an hour? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #266276 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=266276\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> walk 4mph<BR>\n" );
document.write( "cycle 12 mph<BR>\n" );
document.write( "let distance be x miles<BR>\n" );
document.write( "..<BR>\n" );
document.write( "time taken walking = x/4<BR>\n" );
document.write( "..<BR>\n" );
document.write( "time taken riding back = x/12<BR>\n" );
document.write( "x/12+x/4 = 6<BR>\n" );
document.write( "(x+3x)/12=6<BR>\n" );
document.write( "4x=72<BR>\n" );
document.write( "/4<BR>\n" );
document.write( "x=18 miles.<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );