document.write( "Question 373686: A farmer wishes to fence off three identical adjoining rectangular pens, each with 1000 feet of area,What are and so that the least amount of fence is required? \n" ); document.write( "

Algebra.Com's Answer #266274 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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A farmer wishes to fence off three identical adjoining rectangular pens,
\n" ); document.write( " each with 1000 sq/ft of area.
\n" ); document.write( "What are dimensions so that the least amount of fence is required?
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\n" ); document.write( "Total area: 3(1000) = 3000 sq/ft
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\n" ); document.write( "Area:
\n" ); document.write( "L * w = 3000
\n" ); document.write( "L = $\"3000%2Fw\"$
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\n" ); document.write( "Three adjoining pens
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\n" ); document.write( "|_|_|_|w
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\n" ); document.write( "Perimeter (length of fence)
\n" ); document.write( "F = 2L + 4w
\n" ); document.write( "Replace L with $\"3000%2Fw\"$
\n" ); document.write( "F = 2( $\"3000%2Fw\"$ ) + 4w
\n" ); document.write( "F = $\"6000%2Fw\"$ + 4w
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\n" ); document.write( "Find the minimum fencing by graphing this equation: y = $\"6000%2Fx\"$ + 4x
\n" ); document.write( " $\"+graph%28+300%2C+200%2C+-20%2C+100%2C+-200%2C+500%2C+%286000%2Fx%29%2B4x%29+\"$
\n" ); document.write( "You can see minimum occurs when x = 40
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\n" ); document.write( "Find L: L = $\"3000%2F40\"$ = 75 ft is the length
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\n" ); document.write( "Overall dimensions of 75 ft by 40 ft for minimum fencing
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\n" ); document.write( "Check: each pen: 25*40 = 1000 sq/ft\r
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