document.write( "Question 374149: Please help me solve the foci in this equation \"49x%5E2%2F36%2B81y%5E2%2F64=1\". \n" ); document.write( "
Algebra.Com's Answer #266272 by robertb(5830)\"\" \"About 
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Here, \"a%5E2+=+64%2F81\" while \"b%5E2+=+36%2F49\". Now \"b%5E2+=+a%5E2+-+c%5E2\". So that \"36%2F49+=+64%2F81+-+c%5E2\", or \"c%5E2+=+64%2F81+-+36%2F49\".
\n" ); document.write( "\"c%5E2+=+220%2F81%2A49\", or \"c+=+%282sqrt%2855%29%29%2F63\".
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