document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=374083>Question 374083</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a group of 108 persons, composed of men, women, and children, there are 3 times as many children as men, and twice as many women as men. How many are there of each?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #266204 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=266204\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let men be x<BR>\n" );
document.write( "women - 2x<BR>\n" );
document.write( "children = 3x<BR>\n" );
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document.write( "sum =108<BR>\n" );
document.write( "x+2x+3x=108<BR>\n" );
document.write( "6x=108<BR>\n" );
document.write( "/6<BR>\n" );
document.write( "x= 18<BR>\n" );
document.write( "18 men<BR>\n" );
document.write( "36 women<BR>\n" );
document.write( "54 children<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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