Algebra.Com's Answer #266170 by Edwin McCravy(20055)![\"\"](\"/images/stars/stars-13.gif\")  
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A(-5, 0), B(-3,4), C(3,0), D(-2,-4)
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document.write( "If they made a parallelogram, you'd have to show that both pairs of opposite\r\n" );
document.write( "sides are parallel.\r\n" );
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document.write( "So why not graph them? Then you'd see that ABCD is not a parallelogram immediately:\r\n" );
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document.write( "If we connect all the points we have 6 line segments\r\n" );
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document.write( "To do it without graphing you'd have find the slopes of all 6 pairs of points\r\n" );
document.write( "to see if there are two pairs with the same slopes. That's because without\r\n" );
document.write( "graphing you can't tell which pairs of points are the endpoints of the\r\n" );
document.write( "sides and which are the endpoints of the diagonals. So you'd have to find all\r\n" );
document.write( "six to see if two pairs have the same slope. Here's what you'd have to do\r\n" );
document.write( "without graphing:\r\n" );
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document.write( "slope of AB\r\n" );
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document.write( "slope of AC\r\n" );
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document.write( "slope of AD\r\n" );
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document.write( "slope of BC\r\n" );
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document.write( "slope of BD\r\n" );
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document.write( "slope of CD\r\n" );
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document.write( "Then you'd look among the 6 slopes and find that there are not two pairs of\r\n" );
document.write( "lines with the same slopes, which there would have to be if ABCD were a\r\n" );
document.write( "parallelogram. You are always better off graphing. For then if you can't tell\r\n" );
document.write( "just by looking that it's not a parallelogram, you'd at least know which two\r\n" );
document.write( "are diagonals and you won't have to bother finding the slopes of the two\r\n" );
document.write( "diagonals.\r\n" );
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document.write( "Edwin \r
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