document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=41248>Question 41248</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the problem.\r<BR>\n" );
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document.write( "In a right triangle, one acute angle is 54degree more than twice the other. Find each acute angle.\r<BR>\n" );
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document.write( "  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26616 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26616\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of the degrees in a triangle is equal to 180<BR>\n" );
document.write( "One angle: x<BR>\n" );
document.write( "Another angle: 2x + 54<BR>\n" );
document.write( "The last angle: 90<BR>\n" );
document.write( "Equation time!<BR>\n" );
document.write( "(x) + (2x + 54) + (90) = 180<BR>\n" );
document.write( "x + 2x + 54 + 90 = 180<BR>\n" );
document.write( "3x + 144 = 180<BR>\n" );
document.write( "3x = 36<BR>\n" );
document.write( "x = 12<BR>\n" );
document.write( "Plug:<BR>\n" );
document.write( "2x + 54<BR>\n" );
document.write( "2(12) + 54<BR>\n" );
document.write( "24 + 54<BR>\n" );
document.write( "78<BR>\n" );
document.write( "One angle: x = 12<BR>\n" );
document.write( "Another angle: 2x + 54 = 78<BR>\n" );
document.write( "The last angle: 90 </SPAN>\n" );
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