document.write( "Question 373951: Can you please help me. Please!\r
\n" ); document.write( "\n" ); document.write( "Solve 4sin(square)A + 1 = sin(square)A + 2 to the nearest ten minutes or nearest tenth of a degree in the interval ( 0ș less than or equal to A less than 360ș)\r
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Algebra.Com's Answer #266146 by Edwin McCravy(20086)\"\" \"About 
You can put this solution on YOUR website!
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document.write( " 4sinČA + 1 = sinČA + 2\r\n" );
document.write( " -sinČA      -sinČA\r\n" );
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document.write( " 3sinČA + 1 =         2\r\n" );
document.write( "        - 1          -1\r\n" );
document.write( "-----------------------\r\n" );
document.write( " 3sinČA     =         1\r\n" );
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document.write( "      sinČA = \"1%2F3\"\r\n" );
document.write( "     sin(A) = \"%22%22%2B-sqrt%281%2F3%29\"\r\n" );
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document.write( "Use the inverse sine function on the calculator to\r\n" );
document.write( "find the reference angle for A which I call \"ref(A)\"\r\n" );
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document.write( "     ref(A) = 35.26438968°\r\n" );
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document.write( "Since the sign is either + or -, we must include all angles\r\n" );
document.write( "with reference angle 35.3° between 0° and 360°\r\n" );
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document.write( "The reference angle is the first quadrant answer which to \r\n" );
document.write( "the nearest tenth of a degree is \r\n" );
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document.write( "35.3°\r\n" );
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document.write( "the second quadrant angle between 0° and 360° with reference \r\n" );
document.write( "angle 35.3° is gotten by subtracting 35.3° from 180°.\r\n" );
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document.write( "180°-35.3° = 144.7°\r\n" );
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document.write( "the third quadrant angle between 0° and 360° with reference \r\n" );
document.write( "angle 35.3° is gotten by adding 35.3° to 180°.\r\n" );
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document.write( "180°+35.3° = 215.3°\r\n" );
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document.write( "the fourth quadrant angle between 0° and 360° with reference \r\n" );
document.write( "angle 35.3° is gotten by subtracting 35.3° from 360°.\r\n" );
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document.write( "360°-35.3° = 324.7°\r\n" );
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document.write( "Those are the four solutions.\r\n" );
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document.write( "Edwin

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