document.write( "Question 373466: what are the solutions to sin2x=sinx \n" ); document.write( "
Algebra.Com's Answer #266132 by jsmallt9(3758) ![]() You can put this solution on YOUR website! sin(2x) = sin(x) \n" ); document.write( "Using the identity sin(2x) = 2sin(x)cos(x) this becomes: \n" ); document.write( "2sin(x)cos(x) = sin(x) \n" ); document.write( "Subtracting sin(x) from each side: \n" ); document.write( "2sin(x)cos(x) - sin(x) = 0 \n" ); document.write( "Factoring out sin(x): \n" ); document.write( "sin(x)(2cos(x) - 1) = 0 \n" ); document.write( "Using the Zero Product property: \n" ); document.write( "sin(x) = 0 or 2cos(x) - 1 = 0 \n" ); document.write( "Solving the second equation for cos(x) we get: \n" ); document.write( "sin(x) = 0 or cos(x) = 1/2 \n" ); document.write( "So our solutions are all the angles whose sin is 0 or all the angles whose cos is 1/2. Since \"x\" was used for the angle instead of theta, I'm assuming we want radian measure angles. (If you need angles in degrees, just replace all the \n" ); document.write( "Sin is zero at 0 and \n" ); document.write( "x = 0 + \n" ); document.write( "or \n" ); document.write( "x = \n" ); document.write( "(Note: The \"+ \n" ); document.write( "For the second equation, cos is 1/2 for \n" ); document.write( "x = \n" ); document.write( "or \n" ); document.write( "x = \n" ); document.write( "The complete solution is: \n" ); document.write( "x = 0 + \n" ); document.write( "or \n" ); document.write( "x = \n" ); document.write( "or \n" ); document.write( "x = \n" ); document.write( "or \n" ); document.write( "x = \n" ); document.write( " |