document.write( "Question 373899: simplify the factorial (4n+2)!/(4n)! ; and given the folowing sequence 5+5/6, 5+7/8, 5+9/10, 5+11/12, 5+13/14,... write an expression for the apparent nth term assuming n begins with 1. Thanks \n" ); document.write( "

Algebra.Com's Answer #266069 by Fombitz(32388) $\"\"$ $\"About$

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(4n+2)!/(4n)!=((4n+2)(4n+1)(4n)(4n-1)***(3)(2)(1))/((4n)(4n-1)***(3)(2)(1))
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