document.write( "Question 373895: For all values of n and r, where r ≤ n, does nCr always equal nCn-r? Why or why not? \r
\n" ); document.write( "\n" ); document.write( "NO? I am so confused
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Algebra.Com's Answer #266065 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
nCr = nCn-r, considering the definition: \"nCr+=+n%21%2F%28r%21%28n-r%29%21%29\".
\n" ); document.write( "Now .
\n" ); document.write( "Therefore nCr = nCn-r.
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