document.write( "Question 373868: Solve the system.
\n" ); document.write( "Log base x (2y) =3
\n" ); document.write( "Log base x (4y)=2\r
\n" ); document.write( "\n" ); document.write( "I did the change of x^3 = 2y then 2y = x^3 for the first equation. Then, I did the same for the second one. x^2 = 4y. I was trying to solve for y on the first one but I am confused now.\r
\n" ); document.write( "\n" ); document.write( "Thank you.
\n" ); document.write( "EC \n" ); document.write( "

Algebra.Com's Answer #266057 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"2y+=+x%5E3\"$
\n" ); document.write( " $\"y+=+%281%2F2%29%2Ax%5E3\"$
\n" ); document.write( "and
\n" ); document.write( " $\"4y+=+x%5E2\"$
\n" ); document.write( " $\"y+=+%281%2F4%29%2Ax%5E2\"$
\n" ); document.write( "I can say
\n" ); document.write( " $\"%281%2F2%29%2Ax%5E3+=+%281%2F4%29%2Ax%5E2\"$
\n" ); document.write( "Multiply both sides by $\"4\"$
\n" ); document.write( " $\"2x%5E3+=+x%5E2\"$
\n" ); document.write( "Divide both sides by $\"x\"$
\n" ); document.write( " $\"2x+=+1\"$
\n" ); document.write( " $\"x+=+1%2F2\"$
\n" ); document.write( "and, since
\n" ); document.write( " $\"2y+=+x%5E3\"$
\n" ); document.write( " $\"2y+=+1%2F8\"$
\n" ); document.write( " $\"y+=+1%2F16\"$
\n" ); document.write( "and, also,
\n" ); document.write( " $\"4y+=+x%5E2\"$
\n" ); document.write( " $\"4y+=+1%2F4\"$
\n" ); document.write( " $\"y+=+1%2F16\"$
\n" ); document.write( "OK \n" ); document.write( "

\n" );