document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=41225>Question 41225</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The hypotenuse of a right triangle is 25 cm long. one leg is 17 cm longer than the other. Find the length of the shorter leg. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26601 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26601\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (17+x)~2+X~2=25~2 OR 289+34X+X~2+X~2=625 OR 2X~2+34X-336 OR X~2+17x-168=0 or\r<BR>\n" );
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document.write( "(x+24)(x-7)=0 or x=-24 & x=7 answer is 7 cm \r<BR>\n" );
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document.write( "proof 7*7+24*24=625 or 49+576=625 or 625=625  </SPAN>\n" );
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