document.write( "Question 373784: Please help me solve this equation: \"+log+%28sqrt+%28x%5E2-9+%29%29=+2+\" \n" ); document.write( "
Algebra.Com's Answer #266004 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
\"+log+%28sqrt+%28x%5E2-9+%29%29=+2+\",
\n" ); document.write( "\"10%5E2+=+sqrt%28x%5E2+-+9%29\",
\n" ); document.write( "\"100+=+sqrt%28x%5E2+-+9%29\",
\n" ); document.write( "\"10000+=+x%5E2+-+9\",
\n" ); document.write( "\"10009+=+x%5E2\",
\n" ); document.write( "\"x+=+sqrt%2810009%29\"or \"x+=+-sqrt%2810009%29\". Both values satisfy the original equation, and thus are the final answers.
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