document.write( "Question 373769: Find three consecutive integers such that the square of the sum of the smaller two is 105 more than the square of the largest. I would like to know how to solve because I already have the answer which is 6,7,8. \n" ); document.write( "

Algebra.Com's Answer #265998 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!


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document.write( "Hi,
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document.write( "Let x represent the smallest of the three consecutive integers
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document.write( "then (x+1) and (x+2) would be the next two consecutive integers
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document.write( "Write as we Read
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document.write( "[x + (x+1)]^2 = (x+2)^2 +105
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document.write( "solving for x
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document.write( "[2x + 1)]^2 = (x+2)^2 + 105
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document.write( "4x^2 + 4x + 1 = x^2 + 4x + 4 +105
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document.write( "3x^2 - 108 = 0
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document.write( "x^2 = 108/3
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document.write( "x^2 = 36
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document.write( "x = +- 6
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document.write( "three consecutive integers are 6,7,8  Or -6,-5,-4 \n" );
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