document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=41233>Question 41233</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Addition seems simple enough to me, but the minus/negative numbers confuse me on factoring.\r<BR>\n" );
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document.write( "x2 - 6x - 3 = 0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26599 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26599\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This one cannot be factored, so use the quadratic formula<BR>\n" );
document.write( "x^2 - 6x - 3 = 0<BR>\n" );
document.write( "for which we get<BR>\n" );
document.write( "x = (6 ± sqrt(36 + 12)) / 2<BR>\n" );
document.write( "x = (6 ± sqrt(48)) / 2<BR>\n" );
document.write( "x = (6 ± 4*sqrt(3)) / 2<BR>\n" );
document.write( "x = 3 ± 2*sqrt(3) </SPAN>\n" );
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