document.write( "Question 373756: using elimination method how do i solve this
\n" ); document.write( "0.05x+0.05y=44
\n" ); document.write( "0.15x+0.05y=48
\n" ); document.write( "

Algebra.Com's Answer #265975 by amoresroy(361)\"\" \"About 
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using elimination method how do i solve this
\n" ); document.write( "0.05x+0.05y=44
\n" ); document.write( "0.15x+0.05y=48\r
\n" ); document.write( "\n" ); document.write( "Dubtract 2nd equation by 1st equation to eliminate y
\n" ); document.write( ".15x-.05x+.05y-.05y = 48-44
\n" ); document.write( ".10x = 4
\n" ); document.write( " x = 40\r
\n" ); document.write( "\n" ); document.write( "Substitute x = 40 in 1st equation
\n" ); document.write( ".05(40) + .05y = 44
\n" ); document.write( " .05y = 44-2
\n" ); document.write( " y = 840
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