document.write( "Question 373752: Consider the line y=-2/5x+1\r
\n" ); document.write( "\n" ); document.write( "Find the equation of the line that is parallel to this line and passes through the point (-6,2)\r
\n" ); document.write( "\n" ); document.write( "Find the equation of the line that is perpendicular to this line and passes through the point (-6,2)\r
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Algebra.Com's Answer #265973 by amoresroy(361)\"\" \"About 
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Consider the line y=-2/5x+1\r
\n" ); document.write( "\n" ); document.write( "Find the equation of the line that is parallel to this line and passes through the point (-6,2)\r
\n" ); document.write( "\n" ); document.write( "Given:
\n" ); document.write( "Slope: m = -2/5\r
\n" ); document.write( "\n" ); document.write( "point: (-6,2)\r
\n" ); document.write( "\n" ); document.write( "y = mx + b
\n" ); document.write( "2 = -2(-6)/5 + b
\n" ); document.write( "2 = 12/5 + b
\n" ); document.write( "b = 2 - 12/5
\n" ); document.write( "b = (10-12)/5
\n" ); document.write( "b = -2/5\r
\n" ); document.write( "\n" ); document.write( "So given m = -2/5 and b = -2/5, the equation of the line is\r
\n" ); document.write( "\n" ); document.write( "y = -2x/5 -2/5
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