document.write( "Question 373514: Find the other factors by synthetic division:
\n" ); document.write( "y= x^3+2x^2-5x-6 given the factor X-1 \n" ); document.write( "

Algebra.Com's Answer #265932 by jsmallt9(3758) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"y=+x%5E3%2B2x%5E2-5x-6\"$
\n" ); document.write( "Since x-1 is a factor, then (x-1) should divide evenly into $\"x%5E3%2B2x%5E2-5x-6\"$ . We will use synthetic division to divide:
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document.write( "1 |  1  2  -5  -6\r\n" );
document.write( "---     1   3  -2\r\n" );
document.write( "    -------------\r\n" );
document.write( "     1  3  -2  -8\r\n" );
document.write( "

\n" ); document.write( "The remainder, in the lower right corner, is -8. This means that (x-1) is not a factor of $\"x%5E3%2B2x%5E2-5x-6\"$ ! (If (x-1) was a factor then the remainder would be zero.) So either the problem was given to you incorrectly or you posted it incorrectly.

\n" ); document.write( "If we pretend that we did get a reminder of zero, then the rest of the bottom line represents the other factor. The
\n" ); document.write( "1 3 -2
\n" ); document.write( "translates into
\n" ); document.write( " $\"1x%5E2+%2B+3x+-+2\"$
\n" ); document.write( "Then, to find the other factors, we would factor $\"1x%5E2+%2B+3x+-+2\"$ . \n" ); document.write( "

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