document.write( "Question 373648: I am stuck on how to solve this problem:
\n" ); document.write( "\"I travel from town A to town B, a distance of two miles, at a rate of 30mph. At what speed should I make the return trip so that my average speed for the round trip is 60mph? The answer is NOT 90mph.\"
\n" ); document.write( "How would I go about solving this problem?
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Algebra.Com's Answer #265926 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
What they are trying to teach you is
\n" ); document.write( "that an average is never an average of
\n" ); document.write( "2 or more averages or a sum of averages. Always go back
\n" ); document.write( "to the basic definition of an average. In this case:
\n" ); document.write( "(average speed) = (total distance travelled)/(total time elapsed)
\n" ); document.write( "The total distance is \"2+%2B+2+=+4\" mi
\n" ); document.write( "The time for the trip from A to B is \"2%2F30+=+1%2F15\" hr
\n" ); document.write( "Let \"t\" = the total time
\n" ); document.write( "\"4%2Ft+=+60\"
\n" ); document.write( "\"4+=+60t\"
\n" ); document.write( "\"t+=+1%2F15\" hr
\n" ); document.write( "This tells me that the return tip has to be made in \"0\" hrs,
\n" ); document.write( "and that says that there is no way to average \"60\" mi/hr
\n" ); document.write( "for the round trip.
\n" ); document.write( "Suppose the car was a rocket car and could make the return trip
\n" ); document.write( "in \"1%2F600000\" hr
\n" ); document.write( "Now I say that the average speed for the round trip is \"60\" mi/hr
\n" ); document.write( "\"4%2F%281%2F15+%2B+2%2F600000%29+=+60\"
\n" ); document.write( "\"4%2F%284%2F60+%2B+2%2F600000%29+=+60\"
\n" ); document.write( "\"4+=+60%2A%284%2F60+%2B+2%2F600000%29\"
\n" ); document.write( "\"4+=+4+%2B+2%2F10000\"
\n" ); document.write( "There's no way to average \"60\" mi/hr
\n" ); document.write( "no matter how fast you make the return trip\r
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