document.write( "Question 373447: 2x^2+11x-6=0 How do you complete the square of this problem\r
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Algebra.Com's Answer #265893 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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2x^2+11x-6=0 How do you complete the square of this problem
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\n" ); document.write( "The coefficient of x^2 should be 1, divide thru by 2
\n" ); document.write( "x^2 + $\"11%2F2\"$ x - 3 = 0
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\n" ); document.write( "x^2 + $\"11%2F2\"$ x + __ = 3
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\n" ); document.write( "( $\"1%2F2\"$ * $\"11%2F2\"$ )^2 = $\"121%2F16\"$ will complete the square, add to both sides
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\n" ); document.write( "x^2 + $\"11%2F2\"$ x + $\"121%2F16\"$ = 3 + $\"121%2F16\"$
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\n" ); document.write( "x^2 + $\"11%2F2\"$ x + $\"121%2F16\"$ = $\"48%2F16\"$ + $\"121%2F16\"$
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\n" ); document.write( "x^2 + $\"11%2F2\"$ x + $\"121%2F16\"$ = $\"169%2F16\"$
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\n" ); document.write( "(x + $\"11%2F4\"$ )^2 = $\"169%2F16\"$
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\n" ); document.write( "Find the square root of both sides
\n" ); document.write( "x + $\"11%2F4\"$ = +/- $\"sqrt%28169%2F16%29\"$
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\n" ); document.write( "x + $\"11%2F4\"$ = +/- $\"13%2F4%29\"$
\n" ); document.write( "Two solutions
\n" ); document.write( "x = $\"-11%2F4\"$ + $\"13%2F4%29\"$
\n" ); document.write( "x = $\"2%2F4\"$ = $\"1%2F2\"$
\n" ); document.write( "and
\n" ); document.write( "x = $\"-11%2F4\"$ - $\"13%2F4%29\"$
\n" ); document.write( "x = $\"-24%2F4\"$ = -6
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\n" ); document.write( "You can confirm this by checking these values for x in the original problem \n" ); document.write( "

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