document.write( "Question 373603: Mixing a 10 percent solution with a 60 percent solution to get 100 grams of a 50 percent solution. How much of each do i need? \n" ); document.write( "
Algebra.Com's Answer #265885 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "to get 100 grams of a 50 percent solution...
\n" ); document.write( "Let x represent the amount of the 60% solution, (assigning x to the stronger solution)
\n" ); document.write( "then (100g - x)would represent the amount of the 10% solution
\n" ); document.write( "Mixing the 10 percent solution with the 60 percent solution****
\n" ); document.write( ".10(100g - x) + .60x = .50*100g
\n" ); document.write( "solving for x
\n" ); document.write( ".10*100g - .10x +.60x = .50*100g
\n" ); document.write( ".50x = .40*100g
\n" ); document.write( "x = 80g, the amount of the 60% solution, 20g of the 10% solution (100g-80g)\r
\n" ); document.write( "\n" ); document.write( "checking our amswer
\n" ); document.write( ".10*20g + .60*80g = 2g + 48g = 50g = .50*100g \n" ); document.write( "
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