document.write( "Question 373601: One plane ate 520 feet is ascending at a rate of 40 feet per minute, while another plane at 3800 feet is descending at a rate of 120 feet per minute. How long will it take the two planes to be at the same altitude? \n" ); document.write( "
Algebra.Com's Answer #265882 by mananth(16946)\"\" \"About 
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One plane ate 520 feet is ascending at a rate of 40 feet per minute, while another plane at 3800 feet is descending at a rate of 120 feet per minute. How long will it take the two planes to be at the same altitude?
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\n" ); document.write( "Plane A 520 feet vertical rise 40 feet/min
\n" ); document.write( "plane B 3800 feet vertical dip 120 feet per minute.
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\n" ); document.write( "This means that the vertically the speeds are 40 feet / minute & 120 feet /minute travelling towards each other.
\n" ); document.write( "so Add up the speeds
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\n" ); document.write( "120 + 40 = 160 feet per minute.
\n" ); document.write( "the distance between them = 3800 -520 =3280 feet
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\n" ); document.write( "t= d/r
\n" ); document.write( "3280/160\r
\n" ); document.write( "\n" ); document.write( "t = 20.5 minutes. they will be at the same altitude.\r
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\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( "
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