document.write( "Question 373280: 1/2 log base a of (x+2) + 1/2 log base a of (x-2) = 2/3 log base a of 27 \n" ); document.write( "
Algebra.Com's Answer #265879 by jsmallt9(3758)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "With equations with the variable in one or more arguments (or bases) of logarithms, you often start by transforming the equation into one of the following forms: \n" ); document.write( "log(expression) = other-expression \n" ); document.write( "or \n" ); document.write( "log(expression) = log(other-expression) \n" ); document.write( "Since your equation has no \"non-log\" terms, we will aim for the second form. The coefficients of the logarithms in the second form are 1's. Your equation's logarithms have other coefficients. Fortunately we have a property of logarithms, \n" ); document.write( " \n" ); document.write( "An exponent of 1/2 means square root. So I am going to replace the arguments which have this exponent with square roots: \n" ); document.write( " \n" ); document.write( "Also, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Since \n" ); document.write( " \n" ); document.write( "9 \n" ); document.write( "So \n" ); document.write( " \n" ); document.write( "The coefficients are now the 1's we wanted. Next we need to combine the two logarithms into one. And we have a property of logarithms, \n" ); document.write( " \n" ); document.write( "which, using a property of radicals, \n" ); document.write( " \n" ); document.write( "We finally have achieved the second form! From here we use some basic logic: \n" ); document.write( "If the base a logarithms of two expressions are equal then the two expressions must be equal. So: \n" ); document.write( " \n" ); document.write( "To solve this we need to eliminate the square root. So we square both sides: \n" ); document.write( " \n" ); document.write( "which simplifies as follows: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Adding 4 to each side we get: \n" ); document.write( " \n" ); document.write( "Finding the square root of each side: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Whenever you are solving a logarithmic equation you must check your answers (at least to make sure all arguments and bases of logarithms are not zero or negative). And whenever you square both sides of an equation you must check for extraneous solutions. (Extraneous solutions are solutions which work in the squared equation but do not work in the original equation. We have a logarithmic equation and we squared both sides! \n" ); document.write( "When checking, use the original equation: \n" ); document.write( " \n" ); document.write( "Checking \n" ); document.write( " \n" ); document.write( "Using our properties again: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Using the \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Checking \n" ); document.write( " \n" ); document.write( "Already we can see that the two arguments on the left side will be negative (since \n" ); document.write( "So the only solution to your equation is |