document.write( "Question 373587: Salem and vernon are 144 miles apart. A car leaves salem traveling towards vernon, and another car leaves vernon at the same time, traveling towards salem. The car leaving salem avergaes 10 miles per hour more than the other, and they meet after 1 hour and 36 minutes. What are the avergae speeds of the carfs? \n" ); document.write( "
Algebra.Com's Answer #265872 by mananth(16946)\"\" \"About 
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car leaving vernon x mph
\n" ); document.write( "car leaving Salem = x+10 mph
\n" ); document.write( "..
\n" ); document.write( "they both leave towards each other ..
\n" ); document.write( "Add up speeds
\n" ); document.write( "x+x+10 = 2x +10 mph
\n" ); document.write( "..
\n" ); document.write( "time = 1 . 36 mins
\n" ); document.write( "= 1 3/5 hours
\n" ); document.write( "=8/5 hours
\n" ); document.write( "..
\n" ); document.write( "d= rt
\n" ); document.write( "144 = (2x+10)* 8/5
\n" ); document.write( "multiply by 5
\n" ); document.write( "5*144 = 8*(2x+10)\r
\n" ); document.write( "\n" ); document.write( "/8
\n" ); document.write( "5*144/8 = 2x+10
\n" ); document.write( "5*18 = 2x+10
\n" ); document.write( "90=2x+10
\n" ); document.write( "-10....... -10
\n" ); document.write( "90-10=2x
\n" ); document.write( "80=2x
\n" ); document.write( "/2
\n" ); document.write( "40 =x
\n" ); document.write( "x = 40 mph
\n" ); document.write( "other car 50 mph
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( "
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