document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=373490>Question 373490</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I would really appreciate your help!  I need to find the values of p, r, and q.  I have tried to simplify the binomial on the left side of the equals sign, but afterward none of the terms can be combined, leaving me with an unsolvable equation (I have not learned to solve quadratic equations and usually the equations cancel them out nicely):<BR>\n" );
document.write( "(px+q)(2x+5)=6x^2+11x+r </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #265847 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=265847\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> FOILing ___ 2px^2 + (5p + 2q)x + 5q = 6x^2 + 11x + r\r<BR>\n" );
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document.write( "the quantities are equal , so the coefficients (for the x^2, x, and constant terms) are equal\r<BR>\n" );
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document.write( "2p = 6\r<BR>\n" );
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document.write( "5p + 2q = 11\r<BR>\n" );
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document.write( "5q = r </SPAN>\n" );
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